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#1 Posted : Tuesday, May 1, 2012 9:54:06 PM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


Hello,

I am working on an application were one of the requirements is to show a floating dialog bar above the selected annotation object, i am using The Bounding Rectangle (X & Y) properties to consider them as a starting point but none of them worked correctly as the returned point is far from the top, i used the following code:


Private Sub SetAnnotaionBarStylePosition(ByVal obj As AnnObject)
If obj IsNot Nothing Then
'Dim ScreenAnnPoint As AnnPoint = GetScreenCoordinates(obj)
Dim rec As AnnRectangle = GetObjectRealBoundingRectangle(obj)

Dim ScreenAnnPoint As AnnPoint = GetObjectRealPoints(obj, rec.Location)

Dim boundRectangle As AnnRectangle = obj.BoundingRectangle

barAnnotationStyle.FloatLocation = New Point(boundRectangle.X, boundRectangle.Y)
End If
End Sub


"barAnnotationStyle is a third library control that allows a bar to be floated"

So my question :What is the correct way to get the position of the top left part of an AnnObject?
 

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#2 Posted : Wednesday, May 2, 2012 5:37:30 AM(UTC)
Maen Hasan

Groups: Registered, Tech Support
Posts: 1,328

Was thanked: 1 time(s) in 1 post(s)

If you are getting incorrect values when using the obj.BoundingRectangle, you need to use the AnnTransformer class to convert the object's BoundingRectangle to the correct coordinates. Please check the following code:
+-------------------+
Private Function GetObjectRealBoundingRectangle(ByVal obj As AnnObject) As AnnRectangle
' get the un-transformed bounding rectangle
Dim rc As AnnRectangle = obj.BoundingRectangle
'apply the object transformation to this rectangle
Dim t As AnnTransformer = New AnnTransformer(obj.Container.UnitConverter, obj.Transform)
rc = t.RectangleToPhysical(rc)
Return rc
End Function
+-------------------+

If you mean something else, please provide me with more details about the problem.

Thanks,
Maen Badwan
LEADTOOLS Technical Support
 
#3 Posted : Wednesday, May 2, 2012 7:51:57 AM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


Hi,
Thanks for your reply.

I tried using that code before and still am not getting the result that i want.

I know it by comparing the x and y of the MouseEventArgs with the X and Y of the bounding rectangle

for example when i click on the top left part of the annotation (i.e the gripping part to re size it) i capture both the x and y in MouseClick of RasterImageViewer, let's say in my case it's
X=85, Y=137

when i check the x and y of The AnnRectangle returned by GetObjectRealBoundingRectangle
it will be something like
X=243, Y=391 which is way far than the mouse x and y,

i will rephrase my question to how can i convert the rectangle positions to be in relative to the RasterImageViewer
 
#4 Posted : Wednesday, May 2, 2012 7:57:42 AM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


by rectangle positions i meant the top left part of an Annotation Object or it's bounding rectangle.
 
#5 Posted : Wednesday, May 2, 2012 9:26:55 AM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


please, ignore my last question.

When i use the GetObjectRealBounds to get a rectangle, The X and Y point of the location property, do they represent the exact X and Y points as screen coordinates regardless of the RasterImageViewer?

if no then how do i get the exact (top, left) coordinates in screen for an annotation object, regardless of the RasterImageViewer?
 
#6 Posted : Wednesday, May 2, 2012 11:04:48 PM(UTC)
Maen Hasan

Groups: Registered, Tech Support
Posts: 1,328

Was thanked: 1 time(s) in 1 post(s)

The values after the transformation I gave you are for the annotation location in bitmap coordinates.
However, the mouse events give you location values in client coordinates.
If the image is neither scrolled nor zoomed (100% zoom factor), the 2 values should be identical. However, if there's any zooming or scrolling, you can convert between the 2 coordinate systems using Leadtools.Drawing.Transformer class and RasterImageViewer1.Transform as follows:
+--------------------+
' get the un-transformed bounding rectangle
Dim rc As AnnRectangle = automation.CurrentEditObject.BoundingRectangle

'apply the object transformation to this rectangle
Dim t As AnnTransformer = New AnnTransformer(automation.CurrentEditObject.Container.UnitConverter, automation.CurrentEditObject.Transform)

rc = t.RectangleToPhysical(rc)

Dim Trans As Leadtools.Drawing.Transformer = New Leadtools.Drawing.Transformer(RasterImageViewer1.Transform)

'use the following Point
Dim p As PointF = Trans.PointToPhysical(New PointF(rc.X, rc.Y))
+--------------------+

Thanks,
Maen Badwan
LEADTOOLS Technical Support
 
#7 Posted : Wednesday, May 2, 2012 11:30:54 PM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


So if i use this method it will give me the top-left point of the bounding rectangle position relative to The Viewer?
 
#8 Posted : Wednesday, May 2, 2012 11:41:50 PM(UTC)
Ahmad_Hamdan_iLead

Groups: Registered
Posts: 11


thank you very much, after i got the point and used pointToScreen Method on The Viewer i got the right coordinates
 
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